If the radius of the moon is 1.74 × 106 m, calculate the mass of the moon. and radius of the moon, Rm = 1740 km t1 = \(\frac{u}{g}\) …(1) Answer: Answer: Answer: 1. OTP has been sent to your mobile number and is valid for one hour Thus a big stone will fall with the same acceleration as a small stone. Do you agree with his hypothesis or not? We know that G = 6.67 × 10-11 Nm2 kg-2 Question 9. ⇒ Time of ascent = Time of descent. (ii) How long will it take to reach that height? Weight is not a constant quantity. Weight is the force of gravity acting on the body. When a body is thrown vertically upwards, what is its final velocity? Given m1 = 3 kg; m2 = 12 kg t2 = u/g …(2) (a) No Answer: When body is at a distance V from centre of the earth then g = \(\frac{G M}{r^{2}}\). Question Answers, Page 134. So, both the stones will reach the ground at the same time when dropped simultaneously. A: 1 kg B: 9.8 kg C: 9.8 Kg-m/Sec 2 D: 9.8 N. Answer. The universal law of gravitation was able to explain successfully. Wm = \(\frac{G M_{m} m}{R_{m}^{2}}\) …(1) Where, R is the distance of the body from the centre of the earth. Question 10. Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. […] Answer: or – 0.25 = -19.6 h As the mass of the earth is very large as compared to that of the apple, the acceleration experienced by the earth will be so small that it will not be noticeable. Browse from thousands of Gravitation questions and answers (Q&A). Why? (ii) As v = u2 + 2 gs F ∝ m1 × m2…(1) Question 1. At what place on the earth’s surface is the weight of a body maximum? Gravitation Multiple Choice Questions & Answers for competitive exams. The radius of the earth is 6400 km and g = 10 m/s². At the poles. A comprehensive database of gravitation quizzes online, test your knowledge with gravitation quiz questions. Previous: Contents: Next: Answer: It is applied to all the body present in universe It is constant of proportionality in Newton’s universal law of gravitation. Question 4. [NCERT Exemplar] Fp = \(\frac{G \times M_{e} \times m_{1}}{R^{2}}\) …..(1) Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid; and (ii) both of them are hollow, size remaining the same in each case? \(\frac{\iota_{1}}{t_{2}}=\sqrt{\frac{h_{1}}{h_{2}}}\) We = \(\frac{G M_{e} m}{R_{e}^{2}}\) …(2) If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. ∴ New weight becomes 4 times. Calculate the average density of the earth in terms of g, G and R. Q1. For the first stone Question 6. Both stones will take the same time to reach the ground because the two stones fall from the same height. Suppose that the radius of the earth becomes twice of its original radius without any change in its mass. 1. These questions are quite useful to prepare the objective type questions for … The way the world works is exciting. (b) No. (b) At which point is the bal 1 stationary? Question 11. Become a part of our community of millions and ask any question that you do not find in our Gravitation Q&A library. The acceleration produced in the motion of a body falling under the force of gravity is called acceleration due to gravity. Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. Explain why all of them do not fall into the earth just like an apple falling from a tree. Question 3. i.e., First stone would take 3.16 s to reach the ground. If a body of mass m is placed on the surface of moon, then weight of the body on the moon is Yes. \(\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}\) …. Answer: F = mg …(2) Register online for Science tuition on Vedantu.com to score more marks in your examination. The earth attracts an apple. mass of the moon, Mm = 7.4 × 1022 kg For both the stones Similarly, the force of attraction between the earth and the body Q is given by Answer: So, v2 = u2 + 2gs, Why does a body orbiting in space possess zero weight with respect to a spaceship? MCQs on CBSE Class 9 Science Chapter- Gravitation are provided here with answers. The constant ‘G’ is universal because it is independent of the nature and sizes of bodies, the space where they are kept and at the time at which the force is considered. Answer According to question, M S = Mass of the Sun = 2×10 30 kg M E = Mass of the Earth = 6×10 24 kg R = Average distance between the Earth and the Sun = 1.5×10 11 m From Universal law of gravitation, (g) At which point does the bal 1 have the same speed as when it was thrown? F = \(G \frac{m M}{R^{2}}\) …..(1) 1. But we know, acceleration ∝ 1/m. How much do you know about gravitation? The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by 3. Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth. The weight will become 16 times. Answer: One second later, he throws another stone. Question 3. (d) What is the ball’s acceleration at point C? Question 1. Upward motion Professionals, Teachers, Students and Kids Trivia Quizzes to test your knowledge on the subject. It means that the force on the apple due to earth’s attraction is equal to that on the earth due to apple’s attraction. Answer: Answer: 3. State the universal law of gravitation. Question 3. Answer: The accepted value of G is 6.67x 1CT-11 Nm 2 kg-2. = \(\frac{G M m}{4 r^{2}}=\frac{W}{4}\) Answer: Answer: And the mass of body Q=m2 Yes. Answer: Acceleration in downward direction = g Answer: Question 20. Calculate the height of the building. NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. Answer: 6.7 × 10-11 Nm2 kg-2) everywhere in the universe. And Radius of the earth, Re = 6.4 × 106 m. Question 7. When hypothetically M becomes 4 M and R becomes \(\frac{R}{2}\). It will remain the same on the moon, i.e., 9.8 kg. (3) Question 4. But the acceleration due to gravity is represented by the symbol g. Therefore, we can write TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Answer: Answer: Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? Define the standard kilogram. radius of the earth, Re = 6400 km Prove that if the earth attracts two bodies placed at same distance from the centre of the earth with the same force, then their masses are equal. C: 9.8 Kg-m/Sec 2 ) = N ] Q.19 weight of body... 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